Web最近为Clob字段在插入数据时发现当字符的字节数(一个半角字符一个字节,一个全角字符两个字节)在2000-4000之间时报错(ORA-01461:仅可以插入LONG列的LONG值赋值)。. 经过不断查找资料和自己的试验该问题终于得到解决,下边我将自己的心得给大家做一个分享。. WebJun 8, 2011 · Is there a specific reason that you need it to be a Clob? Looking at the sample code, it looks like you are putting it into a String, and Hibernate supports putting Clobs …
View topic - Oracle / String length > 4000 / issue - Hibernate
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Overview of Storing and Managing JSON Data - Oracle Help Center
WebSep 26, 2024 · According to Oracle, from version 8.0 you should be using the CLOB data type instead. The only way that I know of to get a SUBSTR from a LONG variable is to write a PL/SQL procedure that takes a ROWID, then converts that to a 32k variable, and returns 4000 characters to SQL, which can then be used for the SUBSTR function. Web我正在使用Ejb 和JPA 目前基於Hibernate和Oracle g 我有一個包含clob的實體 然后我想保存這種類型的實體。 目前我正在做以下工作, 完美無缺 adsbygoogle window.adsbygoogle .push 然而,這將我的代碼與Hibernate聯系在一起 到目前為止 WebApr 10, 2024 · One option is to just alter table. Here's an example: Table with long datatype column:. SQL> create table test (col long); Table created. Let's populate it: SQL> begin 2 for cur_r in (select text from all_views 3 where text_length < 30000 4 and text is not null 5 ) 6 loop 7 insert into test (col) values (cur_r.text); 8 end loop; 9 end; 10 / PL/SQL procedure … curiously sift ideas for content