Web对于我的情况,阅读相同错误号的答案似乎很难解释。 请提供一些提示以纠正错误。 cannot return value referencing temporary value returns a value referencing data owned by … WebIn the function you can tell whether it was called on a lvalue or rvalue, but that's different from what you're asking about and you'll get to that later. The return type of the function is irrelevent. In my 1st comment I used getO (). to show that a function can return a rvalue reference to an object. So getO () replaces obj in your example
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WebThe non-const version doesn't involve the creation of a temporary, hence it is okay. Actually, you could also switch the const one to not doing that, but that would mean changing the return type to 'char* const&'. Uli -- [ See http://www.gotw.ca/resources/clcm.htm for info about ] [ comp.lang.c++.moderated. First … images of korowai
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WebWhen an argument is passed by reference, a variable is created in the function to hold the argument's value. the function cannot access the argument's value. a temporary variable is created in the calling program to hold the argument's value. the function accesses the argument's original value in the calling program. User Defined Methods ICSE WebMay 9, 2024 · All records will be gone at the end of this function. So you can't return references to records that are gone. And you can't return both owned struct and a … WebSep 2, 2024 · rvalue references extend the lifespan of the temporary object to which they are assigned. Non-const rvalue references allow you to modify the rvalue. Important: lvalue references can be assigned with the rvalues but rvalue references cannot be assigned to the lvalue . C++ #include using namespace std; int main () { int a = 10; images of koo stark